0=18b^2-3b-10

Solution for 0=18b^2-3b-10 equation:

0=18b^2-3b-10

We move all terms to the left:

0-(18b^2-3b-10)=0

We add all the numbers together, and all the variables

-(18b^2-3b-10)=0

We get rid of parentheses

-18b^2+3b+10=0

a = -18; b = 3; c = +10;
Δ = b2-4ac
Δ = 32-4·(-18)·10
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-27}{2*-18}=\frac{-30}{-36}
=5/6
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+27}{2*-18}=\frac{24}{-36}
=-2/3
$